Answer:
[B]?(c)
In sixth period, the orbitals
which are filled are:
6s 4f 5d and 6p
[C]?(c)
Long form of the periodic table
can accommodate 118 elements.
[D]?(a)
The electronic configuration of
the element with atomic number 43 is:
\[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{10}}4{{s}^{2}}4{{p}^{6}}4{{d}^{5}}5{{s}^{2}}\]
It is a transition metal having
5 electrons in penultimate d-orbital. Thus, the element above this element has
the following electronic configuration.
\[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{5}}4{{s}^{2}}\]
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