Answer:
The given reaction is:
\[{{N}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons
2NO(g)\]
\[{{K}_{c}}=\frac{{{[NO]}^{2}}}{[{{N}_{2}}][{{O}_{2}}]}=\frac{{{(2.8\times
{{10}^{-3}})}^{2}}}{3\times {{10}^{-3}}\times 4.2\times {{10}^{-3}}}\]
\[=0.622M\]
You need to login to perform this action.
You will be redirected in
3 sec