Answer:
(i) \[\Delta
{{n}_{g}}=2-1=1,\,\,i.e.,\,\,\Delta {{n}_{g}}>0\]
On decreasing pressure, the equilibrium will shift towards
forward direction, i.e., towards greater volume direction.
(ii) Since, gaseous
components are not present on both sides of reaction hence there will be no
effect of pressure change.
(iii) \[\Delta
{{n}_{g}}=4-4=0\]
There is no change in the number of gaseous moles hence
there will be no effect of pressure change.
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