Answer:
(i) Addition of reactant (\[{{H}_{2}}\])
will shift the equilibrium towards forward direction.
(ii) Addition of
product (\[C{{H}_{3}}OH\]) will increase the rate of backward reaction, hence
the equilibrium will shift in backward
direction.
(iii) Removal of CO,
i.e., decrease in concentration of reactant will also shift the equilibrium in
backward direction.
(iv) Removal of\[C{{H}_{3}}OH\], i.e., decrease in
concentration of product will shift the equilibrium towards forward direction.
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