Answer:
(a) \[HCl\to
{{H}^{+}}+C{{l}^{-}}\]
\[[{{H}^{+}}]=[HCl]=0.003M\]
\[pH=-\log [{{H}^{+}}]\]
\[=-\log [0.003]=2.52\]
(b) \[NaOH\to N{{a}^{-}}+O{{H}^{-}}\]
\[[O{{H}^{-}}]=[NaOH]=0.005M\]
\[pH=14-2.301=11.699\]
(c) \[HBr\to {{H}^{+}}+B{{r}^{-}}\]
\[[{{H}^{+}}]=[HBr]=0.002M\]
\[pH=-\log [{{H}^{+}}]=-log[0.002]=2.6989\]
(d) \[KOH\to {{K}^{+}}+O{{H}^{-}}\]
\[[O{{H}^{-}}]=[KOH]=0.002M\]
\[pOH=-\log [O{{H}^{-}}]\]
\[=-\log [0.002]\]
\[=2.6989\]
\[pH=14-2.6989=11.3011\]
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