Answer:
Mass of organic compound, W =
0.157 g
Mass of barium sulphate,
\[{{W}_{1}}=0.4813g\]
\[\underset{233g}{\mathop{BaS{{O}_{4}}}}\,\equiv
\underset{32g}{\mathop{S}}\,\]
Percentage
of sulphur = \[\frac{32}{233}\times \frac{{{W}_{1}}}{W}\times 100\]
\[=\frac{32\times
0.4813\times 100}{233\times 0.157}=\mathbf{42}\mathbf{.10%}\]
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