Answer:
(i)\[\mathbf{HCOOH}\text{
}:C{{H}_{3}}COOH,\text{ }C{{H}_{3}}C{{H}_{2}}COOH\], \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COOH,\text{
}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}\text{ }COOH\]
(ii)\[\mathbf{C}{{\mathbf{H}}_{\mathbf{3}}}\mathbf{COC}{{\mathbf{H}}_{\mathbf{3}}}:C{{H}_{3}}C{{H}_{2}}COC{{H}_{3}},\]\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COC{{H}_{3}},\text{
}C{{H}_{3}}{{(C{{H}_{2}})}_{3}}COC{{H}_{3}},\]\[C{{H}_{3}}{{(C{{H}_{2}})}_{4}}COC{{H}_{3}}\]
(iii)\[{{\mathbf{H}}_{\mathbf{2}}}\mathbf{C}=\mathbf{C}{{\mathbf{H}}_{\mathbf{2}}}:C{{H}_{3}}CH==C{{H}_{2}},\]\[C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}},\text{
}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CH=C{{H}_{2}},\]\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}CH=C{{H}_{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec