Answer:
(c, d)
Number of molecules of \[{{O}_{2}}\]
in 16 g \[{{O}_{2}}\]
\[=\frac{16}{32}\times 6.023\times
{{10}^{23}}\]
\[=0.5\times 6.023\times {{10}^{23}}\]
0.5 moles are present in 14 g \[{{N}_{2}}\]
and 1 g \[{{H}_{2}}\], hence these samples will also have \[(0.5\times
6.023\times {{10}^{23}})\]) molecules.
(c) Number of molecules of \[{{N}_{2}}\] \[=\frac{w}{mol.wt}\times
6.023\times {{10}^{23}}\]
\[=\frac{14}{28}\times
6.023\times {{10}^{23}}\]
\[=0.5\times
6.023\times {{10}^{23}}\]
Number of molecules of \[{{H}_{2}}=\frac{1}{2}\times
6.023\times {{10}^{23}}\]
\[=0.5\times 6.023\times {{10}^{23}}\]
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