Answer:
\[{{n}_{B}}(NaOH)=\frac{{{w}_{B}}}{{{m}_{B}}}=\frac{4}{40}=0.1\]
\[{{n}_{A}}({{H}_{2}}O)=\frac{{{w}_{A}}}{{{m}_{A}}}=\frac{36}{18}=2\]
\[{{x}_{B}}=\frac{{{n}_{B}}}{{{n}_{A}}+{{n}_{B}}}=\frac{0.1}{2+0.1}=\frac{0.1}{2.1}=0.0476\]
\[{{x}_{A}}=(1-0.0476)=0.9524\]
Volume of solution = \[\frac{\text{Mass}\,\text{of}\,\text{solution}}{\text{Density}\,\text{of}\,\text{solutions}}\]
\[=\frac{(4+36)}{1}=40mL\]
Molarity of solution can be
calculated as:
\[M=\frac{{{w}_{B}}\times
1000}{{{m}_{B}}\times V}=\frac{4\times 1000}{40\times 40}=2.5\]
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