Answer:
Let volume of solution = 1
litre, i.e., 1000 mL
Mass of solution \[=1000\times
1.25=1250\text{ }g\]
Mass of
solute dissolved \[=3\times 58.5=175.5\text{ }g\]
Mass of
solvent \[=1250-175.5=1074.5\text{ }g\]
Molality \[(m)=\frac{{{w}_{B}}\times
1000}{{{m}_{B}}\times {{w}_{A}}}\]
\[=\frac{175.5\times 1000}{58.5\times 1074.5}=2.79\]
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