Answer:
We know, \[PM=dRT\]
For a gas we may
use:
\[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{d}_{1}}{{T}_{1}}}{{{d}_{2}}{{T}_{2}}}\,\,\,\,\,\,\,\,\,\,.....(i)\]
\[{{P}_{1}}=2bar,\] \[{{P}_{2}}=1.01325bar\]
\[{{d}_{1}}=5.46g/d{{m}^{3}},\] \[{{d}_{2}}=?\]
\[{{T}_{1}}=300K,\] \[{{T}_{2}}=273K\]
Substituting these
values in Eqn. (i)
\[\frac{2}{1.01325}=\frac{5.46\times
300}{{{d}_{2}}\times 273}\]
\[{{d}_{2}}=3.04g/d{{m}^{3}}\]
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