Answer:
\[\Delta
E=({{E}_{3}}-{{E}_{2}})\]
\[=-\frac{2.18\times
{{10}^{-18}}}{{{3}^{2}}}-\left( -\frac{2.18\times {{10}^{-18}}}{{{2}^{2}}}
\right)\]\[=\left( \frac{1}{4}-\frac{1}{9} \right)\times 2.18\times
{{10}^{-18}}\]
\[=\frac{5}{36}\times 2.18\times
{{10}^{-18}}J\]
\[=3.027\times {{10}^{-19}}J\]
\[hv=3.027\times {{10}^{-19}}\]
\[v=\frac{3.027\times
{{10}^{-19}}}{6.626\times {{10}^{-34}}}\]
\[=4.6\times {{10}^{14}}Hz\]
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