Answer:
(i) \[{{E}_{n}}=\frac{-{{E}_{1}}}{{{n}^{2}}}\]
\[=\frac{-2.18\times
{{10}^{-18}}}{25}\]
\[=-8.72\times {{10}^{-20}}J\]
(ii) \[r=\frac{{{n}^{2}}}{Z}\times
0.529\overset{{}^\circ }{\mathop{\text{A}}}\,\]
\[=\frac{25}{1}\times
0.529\overset{{}^\circ }{\mathop{\text{A}}}\,\]
\[=13.225\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
or 1.3225 nm
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