Answer:
Angular momentum of electron can be calculated as,
\[m\upsilon
r=\frac{h}{2\pi }\]
\[2\,\pi
r=n\frac{h}{m\upsilon }\]
\[2\,\,\pi
r=n\lambda \]
Circumference \[=n\times \,de\] Broglie wavelength of
electron
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