Answer:
Z is \[B{{F}_{3}}\] and X is\[{{B}_{2}}{{H}_{6}}\].
\[\underset{(Z)}{\mathop{4B{{F}_{3}}}}\,++3Lil{{H}_{4}}\xrightarrow{{}}\underset{(X)}{\mathop{2{{B}_{2}}{{H}_{6}}}}\,+3LiCl+3AlC{{l}_{3}}\]
Diborane \[({{B}_{2}}{{H}_{6}})\]
reacts readily with water liberating hydrogen.
\[\underset{(X)}{\mathop{{{B}_{2}}{{H}_{6}}}}\,+6{{H}_{2}}O\xrightarrow{{}}\underset{(Y)}{\mathop{2{{H}_{3}}B{{O}_{3}}}}\,+6{{H}_{2}}\]
\[\underset{(X)}{\mathop{{{B}_{2}}{{H}_{6}}}}\,+3{{O}_{2}}\xrightarrow{{}}{{B}_{2}}{{O}_{3}}+3{{H}_{2}}O\]
The reaction is highly
exothermic.
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