Answer:
(a,
d)
(a) \[{{E}_{t}}\]
and \[{{E}_{r}}\]
both obey
Maxwell?s distribution independent of each other.
(d)
Kinetic energy of translation/molecule,
\[{{E}_{t}}=3\left(
\frac{1}{2}{{k}_{B}}T \right)=\frac{3}{2}{{k}_{B}}T\]
Kinetic
energy of rotation/molecule,
\[{{E}_{r}}=2\left(
\frac{1}{2}{{k}_{B}}T \right)={{k}_{B}}T\]
Clearly,
\[{{E}_{r}}=\frac{2}{3}{{E}_{t}}\]
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