Answer:
Mean free path, \[\lambda
=\,\frac{KT}{\sqrt{2}\,\pi \,{{d}^{2}}P}\]
If
P and T are same for all type of molecules.
\[\lambda
\propto \,\frac{1}{{{d}^{2}}}\]
\[\therefore
\] \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\,=\,{{\left( \frac{{{d}_{
& 2}}}{{{d}_{1}}} \right)}^{2}}\,=4\]
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