Answer:
(a) Average K.E. of
a molecule of a gas
\[=\frac{3}{2}\,kT\]
Thus,
average K.E of a molecule is independent of its mass, therefore, molecules A, B
and C will have the same average K. E
(a) \[{{\upsilon
}_{rms}}\,\alpha \frac{1}{\sqrt{m}}\]
Thus,
\[{{({{\upsilon }_{rms}})}_{c}}\,>\,{{({{\upsilon }_{rms}})}_{B}}>\,{{({{\upsilon
}_{rms}})}_{c}}\]
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