Answer:
Here,\[{{10}^{8}}N{{m}^{-2}},\]
\[{{10}^{8}}\times \pi
{{r}^{2}}={{10}^{8}}\times \left( 22/7 \right)\times {{\left( 1\cdot 5\times
{{10}^{-2}} \right)}^{2}}=7\cdot 07\times {{10}^{4}}N\]
Volumetric strain \[110\times
{{10}^{9}}\]
\[N{{m}^{-2}}\]
\[190\times {{10}^{9}}\] Fractional
change in volume = \[N{{m}^{-2}}\]
\[\text{Y=}\frac{\text{4F/
}\!\!\pi\!\!\text{ }{{\text{D}}^{\text{2}}}}{\text{strain}}\]
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