Answer:
Thermal strees \[=Y\,\alpha
\,\Delta T\,=2\times \,{{10}^{11}}\times \,{{10}^{-5}}\,\times \,200\]
\[=4\times
{{10}^{8}}\,N{{m}^{-2}}\]
\ Tension, T = Thermal strees × Area
of cross-section
\[=4\times
{{10}^{8}}N{{m}^{2}}\times {{10}^{4}}{{m}^{2}}\]
\[=4\times
{{10}^{4}}N\]
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