question_answer 5)

Two wires of diameter 0.25 cm, one made of steel and the other made of brass are loaded as shown in Fig. 3. The unloaded length wire is 1.5 m and that of brass wire is 1.0 m. Compute the of the steel and the brass wires,                     

Answer:

For steel -wire; total force on steel wire;                 [=1cdot 074times {{10}^{-2}}m=1cdot text{074 cm}]  Or [6cdot 9times {{10}^{7}}Pa] For brass wire, [{{10}^{-3}}] Or [=6cdot 9times {{10}^{7}}Pa;] As,   [=6cdot 9text{ }!!times!!text{ 1}{{text{0}}^{text{7}}}text{ }!!times!!text{ }left( text{22/7} right)text{ }!!times!!text{ }{{left( text{3 }!!times!!text{ 1}{{text{0}}^{text{-3}}} right)}^{text{2}}}] Or  [therefore ]= [=4left[ 6cdot 9text{ }!!times!!text{ 1}{{text{0}}^{text{7}}}text{ }!!times!!text{ }frac{text{22}}{text{7}}text{ }!!times!!text{ 9 }!!times!!text{ 1}{{text{0}}^{text{-6}}} right]=7cdot 8times text{1}{{text{0}}^{text{3}}}text{N}]       [1cdot 1times {{10}^{8}}Pa.] And  [0cdot 32{{m}^{3}}]         [=11cdot 6times {{10}^{11}}N{{m}^{-2}}]            [p=1cdot 1times {{10}^{8}}pa;]