Answer:
Here, \[\vartriangle {{l}_{1}}=\vartriangle l;\]
\[{{F}_{1}}=F\]
Mass of glycerine flowing per second,
\[{{\text{a}}_{\text{2}}}\text{=4
}\!\!\times\!\!\text{ 0 }\!\!\times\!\!\text{
1}{{\text{0}}^{\text{-5}}}{{\text{m}}^{\text{2}}}\text{,}\]
Volume of glycerine flowing per second,
\[{{l}_{2}}=3\cdot 5m,\]
If \[\vartriangle {{l}_{2}}=\vartriangle
l;\]is the difference of pressure between two ends of the tube, then using
poiseuilles formula, we have \[{{F}_{2}}=F\]or \[{{Y}_{1}},{{Y}_{2}}\]
\[\therefore \]
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