Answer:
Here,
\[=\sqrt{\frac{190\times
{{10}^{9}}}{110\times {{10}^{9}}}}=\sqrt{\frac{19}{11}}=1\cdot 31\]
Density of soap solution,
\[0\cdot
065c{{m}^{2}}.\]
Excess pressure inside the soap
bubble,
\[{{Y}_{steel}}=2\times
{{10}^{11}}N{{m}^{-2}}.\]
Excess pressure inside the air
bubble,
\[14\cdot
5kg;l=r=1m;v=2\]
Total
pressure inside the air bubble at depth h in soap solution =p' + atmospheric
pressure + h p g =
\[A=0\cdot 065\times {{10}^{-4}}{{m}^{2}}\]
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