Answer:
The maximum force, which the bigger piston can bear, \[F=3000\,kg\,f=3000\times
9.8\,N\]
Area of piston, \[A=425\,c{{m}^{2}}=425\times
{{10}^{-4}}\,{{m}^{2}}\]
\[\therefore
\] Maximum pressure on the bigger piston,
\[\times
\left[ \frac{1}{1\cdot 5\times {{10}^{-3}}}-\frac{1}{3\times {{10}^{-3}}}
\right]\]
Since the liquid transmits pressure equally, therefore the
maximum pressure the smaller piston can bear is \[=4\cdot 97\times {{10}^{-3}}m\]
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