Answer:
(c) \[\frac{{{R}_{2}}}{{{R}_{1}}}\,=\,\frac{\sin
\,2{{\theta }_{2}}}{\sin \,2{{\theta }_{1}}}\,=\,\frac{\sin \,{{90}^{o}}}{\sin
\,{{30}^{o}}}\,\,=\,\frac{1}{1/2}\,=2\]
\[\therefore \]\[{{R}_{2}}=2{{R}_{1}}=\,2\times
\,50\,=100\,\,m\].
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