Answer:
(a) As the change in speed is greatest in interval 2, so magnitude of average acceleration is greatest in interval 2.
(b) Obviously from the graph, average speed is greatest in interval 3.
(c) is positive in all three intervals, a is positive in the intervals 1 and 3 as speed is increasing in these intervals. But a is negative in interval 2 as speed is decreasing in this interval.
(d) At the points A, B, C and D, the v-t graph is parallel to the time-axis or has a zero slope, so a = 0 at all these points.
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