Answer:
Here, \[m=50\,kg;\] Max. extension, \[y=20-0=20\,cm=0.2\,m;\,T=0.6\,s;\]
Max. Force, \[F=mg=50\times N\]
\[\text{B=}\sqrt{\text{2}}\text{cm}\] \[\frac{\text{Bsin
}\!\!\alpha\!\!\text{ }}{\text{Bcos }\!\!\alpha\!\!\text{
}}\text{=}\frac{\text{1}}{\text{1}}\]
As, \[\tan \alpha =1\]
\[\text{ }\!\!\alpha\!\!\text{ = }\!\!\pi\!\!\text{ /4}\] \[\text{5
}\!\!\pi\!\!\text{ /4}\]
\[0\cdot 60\] Weight of body \[9\cdot
8\]
\[=219.1\,N=22.36\,\,kgf\]
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