Answer:
When \[{{\left( \text{10 }\!\!\pi\!\!\text{ }
\right)}^{\text{2}}}\text{ }\!\!\times\!\!\text{ 0=0}\] and \[\text{V=10 }\!\!\pi\!\!\text{
}\!\!\times\!\!\text{ }\sqrt{{{\left( 0\cdot 05
\right)}^{2}}-{{0}^{2}}}\text{10 }\!\!\pi\!\!\text{ }\!\!\times\!\!\text{
0}\cdot 05=0\cdot \text{5 }\!\!\pi\!\!\text{ mk/s}\]
\[\omega \] From \[x=A\]\[\cos (\omega
t+\theta );\,{{x}_{0}}=A\cos \theta \]
velocity \[{{\upsilon }_{0}}\]\[\text{
}\!\!\omega\!\!\text{ ,}{{\text{x}}_{\text{0}}}\]
Squaring and adding (i) and (ii), we get
\[{{\text{ }\!\!\upsilon\!\!\text{ }}_{\text{0}}}\text{.}\]
\[t=0,x={{x}_{0}}\]
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