Answer:
(a)
\[{{u}_{\max }}\,=\,\omega r\]
and
\[{{a}_{\max }}={{\omega }^{2}}r\]
\[\therefore
\] \[\omega
=\,\frac{{{a}_{\max }}}{{{u}_{max}}}\,=\frac{60}{30}\,=2\]
or \[T=\,\frac{2\pi
}{\omega }=\,\pi s\]
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