Answer:
Here, amplitude, \[r=5\,cm\,=5\times
{{10}^{-2}}\,m\].
\[\omega
=\,\sqrt{\frac{k}{M}}\,=\,\sqrt{\frac{50}{2}}\,=\,5\,\,rad\,\,{{s}^{-1}}\]
Using
x \[x=r\,\sin \,\omega t,\] we get
\[x=(5\times
{{10}^{-2}}\,\sin \,5t)\,m\]
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