Answer:
Here, \[k=1200\,\,N{{m}^{-1}};\] \[m=3.0\,kg,\] \[a=2.0\,cm=0.02\,m\]
(a) Frequency,
\[\text{N}{{\text{m}}^{\text{-1}}}\]
(b) Acceleration, \[3\cdot 0\]
Acceleration
will be maximum when y is maximum, i.e., \[y=a\]
\[2\cdot
0\] Max acceleration,
\[\text{N}{{\text{m}}^{\text{-1}}}\]
(c)
Max. speed of the mass will be when it is passing through the mean position,
which is given by
\[3\cdot 0\]
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