Answer:
We
know that moment of inertia, \[I=\sum{m{{r}^{2}}}\]. In case of a hollow
cylinder of radius R, all its mass \[(m)\] lies at a distance
R from the axis of symmetry. But in case of solid sphere of radius R and mass
M, most of its mass lies at a distance smaller than R. Hence, \[{{I}_{\text{cylinder}}}>{{I}_{\text{solid}}}\]
(about the axes of symmetry).
You need to login to perform this action.
You will be redirected in
3 sec