Answer:
(a)
Frictional
force on drum of radius R (F)
(b)
\[\Sigma \,F=\,O,\,\,{{F}_{1}}\,=\,{{F}_{2}}=F\]
\[{{\tau
}_{ext}}\,=F\times \,3R\]
(c) When force of
friction cases
\[{{\upsilon
}_{1}}\,={{\upsilon }_{2}}\] or \[R{{\omega }_{1}}\,=2R\,{{\omega }_{2}}\]
\[\therefore
\] \[\frac{{{\omega }_{1}}}{{{\omega }_{2}}}=2\].
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