Answer:
Thermal stress = K
× strain
\[=\,K\,\frac{\Delta
V}{V}\]
Now
\[\gamma =\,\frac{\Delta V}{V\Delta T}\] or \[\frac{\Delta V}{V}=\,\gamma \Delta T\]
\[\therefore
\] Thermal
stress \[=K\,\gamma \,\,\Delta \,T\]
\[=3K\,\alpha
\,\Delta T\] \[(\therefore \,\,\gamma \,=\,3\alpha
)\]
\[=3\times
\,140\,\times \,{{10}^{9}}\,\times \,1.7\,\times \,{{10}^{-5}}\,\times \,20\]
\[=1.428\,\times
\,{{10}^{8}}\,N{{m}^{-2}}\]
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