Answer:
Let original freq. of sitar string A be and original
freq. of sitar string B be
As
number of beats/sec.=6
or 318 Hz
When
tension in A is reduced, its frequency reduces
As
number of beats/sec decreases to 3 therefore, frequency of B= 324 - 6 = 318 Hz.
You need to login to perform this action.
You will be redirected in
3 sec