Answer:
\[v=\frac{1}{2L}\,\sqrt{\frac{T}{\mu
}}\,=\,\frac{1}{2L}\,\sqrt{\frac{T}{\pi {{r}^{2}}\rho }}\]
When
\[r'=3r\]
\[\therefore
\] \[v'\,=\frac{1}{2L}\,\sqrt{\frac{T}{9\pi {{r}^{2}}\rho
}}\,=\frac{1}{3}\,v\]
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