11th Class Physics Waves / तरंगे

  • question_answer 56)
                      The pattern of standing waves formed on stretched string at two instants of time are shown in fig. The Velocity of two waves superimposing to form stationary waves is \[360\,\,m\,{{s}^{-1}}\] and their frequencies are 256 Hz.          (a) Calculate the time at which the second curve is plotted. (b) Mark nodes and antinodes on the curve. (c) Calculate the distance between ?A? and C?.

    Answer:

                      \[\lambda \,=\,\frac{\upsilon }{2}\,=\frac{360}{26}\,=1.41\,m.\]                 \[t'\,=\frac{2\lambda }{v}\,=\,s\frac{2\times 1.41}{360}\,=\,7.8\,\times {{10}^{-3}}s\]                 (b) Nodes at A, B, C, D and E.                 Antinodes at A? and C? (c) Distance between A? and C?


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