Answer:
A string under a
given tension, can be made to vibrate in more than one segment giving rise to
various modes of vibration. But due to boundary condition, the string can
oscillate only in special patterns which are called normal modes*. The
frequencies of vibration of a string for all these modes of vibration are
different as is clear from the following discussion. In fact, a string is said
to vibrate in a normal mode if it vibrates according to the equation
\[y=2A\sin
kx\cos \omega t\] ? (i)
From
eqn. (i), for a point to be a node,
\[x=n\lambda
/2,\] where
\[n=0,\,1,\,2,\,3\] ?
(ii)
As
we have already said, the two ends to which the string (of length L) is
attached are nodes. If we choose one of the ends as \[x=0\], then the other is \[x=L\].
For this end \[(x=L)\] to
be a node, from eqn. (ii)
\[L=n\lambda
/2\] or \[\lambda =\frac{2L}{n},\] where \[n=1,\,2,\,3,\] ?(iii)
Clearly,
\[{{\lambda }_{1}}=2L,\,{{\lambda }_{2}}=L,\,{{\lambda
}_{3}}=\frac{2L}{3}.....\]
The frequencies
corresponding to these wavelength are given by
\[v=\frac{\upsilon
}{\lambda }=\frac{\upsilon }{2L/n}=n\left( \frac{\upsilon }{2L} \right),\]
where \[n=1,\,2\,.....\]
? (iv)
where
\[\upsilon \] is
the speed of travelling waves on the string.
(a)
If \[n=1,\,v=\frac{\upsilon }{2L}\] and it is called the fundamental frequency
or first harmonic**. The corresponding mode is called fundamental mode of
vibration.
In
this case, the string vibrates in one segment.
(b)
If \[n=2,\,{{v}_{1}}=2\left( \frac{\upsilon }{2L} \right)=\frac{\upsilon }{L}\]
and it is
called second harmonic or first overtone. It is obvious that \[{{v}_{1}}=2v\].
In this case, the string vibrates in two segments.
(c)
If \[n=3,\,{{v}_{3}}=3\left( \frac{\upsilon }{2L} \right)=\frac{3\upsilon
}{2L}\] and
it is called third harmonic or second overtone. Clearly, \[{{v}_{3}}=3{{v}_{1}}\].
In this case, the string vibrates in three segments.
(d)
If \[n=4,\,{{v}_{4}}=4{{v}_{1}}\]
All these modes of
vibrations with their corresponding wavelengths are shown in (a), (b) and (c),
respectively.
Obviously,
\[{{v}_{1}}:{{v}_{2}}:{{v}_{3}}:{{v}_{4}}=1 & & :2 & :3:4\]
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