Answer:
Given curve is 4y = 3x2
??
(1)
and 2y = 3x + 12
(1) and (2)
x2
= 2x + 8
x2
? 2x ? 8 = 0
(x ? 4)
(x + 2) = 0
x = 4, ?
2
(2) y = 12
when x = 4
and y = 3 when x = ?2
points
of intersection are (4, 12) and (?2, 3)
Required area = Shaded area
= 36 ? 16 + 9 ? 2 = 27.
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