question_answer 1)

Find the approximate value of f(5.001) where f(x) = x3 – 7x2 + 15.  

Answer:

5.001 = 5 + 0.001       Let               = 140 ? 175 = ?35       Taking y = f(x)                                             ? (1)                                           ?. (2)       (2) ? (1)                      ?. (3)       Using approximation       (3)  dy = f(5 + 0.001) ? f(5)                   = (3x2 ? 14x)       = (75 ? 70) (00001) ? 35       = 0.005 ? 35 = ?34.995