Answer:
= 2(?4 +
4) + 3 (?6 + 4) + 5 (3 ? 2)
= 0 ? 6 + 5 = ?
1 0
Therefore A is
non-singular matrix so A?1 exists.
A11 =
0; A12 = 2; A13 = 1
A21 =
?1; A22 = ?9; A23 = ?5
A31 =
2; A32 = 23; A33 = 13
Adj A =
The given system
can be expressed as AX = B, where
Now AX = B
On equating, we
get x = 1, y = 2 and z = 3.
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