Answer:
Let
Operate
Taking 1 + a2
+ b2 as common from C1 and C2, we get
Expand along C1,
we get
= (1 + a2
+ b2)2
= (1 + a2
+ b2)2 [1 ? a2 ? b2 + 2a2
+ 2b2]
= (1 + a2
+ b2)2 (1 + a2 + b2)
= (1 + a2
+ b2)3
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