and
find
(AB)?1.
Answer:
= 1 (3 ? 0) ?
2(?1 ? 0) ?2 (2 ? 0)
= 3 + 2 ? 4 = 1 
0
Therefore B is
non-singular matrix so B?1 exists here
B11 =
3; B12 = 1; B13 = 2
A21 =
2; B22 = 1; B23 = 2
A31 =
6; B32 = 2; B33 = 5
adj 
Now 
Also we know
that, (AB)?1 = B?1 A?1
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