Each
machine is available for a maximum of 6 hours per day. If the profit on each
toy of type A is Rs7.50 and that on each toy of type B is Rs.5, show that 15
toys of type A and 30 of type B should be manufactured in a day to get maximum
profit.
Answer:
Let
number of toys of type A = x
And
number of toys of type B = y
The
number of minutes to make one unit of toy of each type is given below :
The
above L.P.P. is given as
Maximize
Profit P = 7.50x P = 7.50x + 5y, subject to the constraints 12x + 6y 
, 18x , 6x + 9y
i.e.
2x + y 
2x
+ 3y 
L1
: 2x + y = 60 L2 : 2x + 3y = 120
Z is maximum
at E(15, 30) and maximum profit is Rs.262.50.
You need to login to perform this action.
You will be redirected in
3 sec
