Answer:
Let
Depot A transport x litres of petrol to petrol pump D, y litres to e and 7000 ?
(x + y) litres to C.
Also,
let depot B transport (4500-x) lietres of petrol to petrol pump to D, (3,000-y)
litres to E and x + y ? 3500 to F.
Graphical
representation of the problem is given below :
Here
objective function is
C
= 7x + 6y + 3 (700 ? x ? y) + 3 (4500 ? x) + 4 (3000 ? y) + 2(x + y ? 3500)
i.e.
C = 3x + y + 39500 subject to the constraints x + y x + y ?3500
i.e.
Minimize, C = 3x + y + 39,500 subject to the constraints x + y
L1 :
x + y = 7000 L2 : x + y = 3500
Here
cost is minimum at H(500, 3000)
Hence
from depot A, 500/, 3000/, 3500/ petrol will be transported to petrol pumps D,
e,f F respectively and from Dept B, 4000/, ol, ol petrol will be transported to
petrol pumps D, E, F respectively.
Since
transportation cost of 10/is Rs.1 per km
Total
transportation cost
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