Answer:
Black balls = 10 n(B) = 10
Red balls = 8 n (R) = 8
Total balls = 10 +
8 = 18
(i)P (both balls
are red) = P (RR) = P(R) P(R)
events
rare independent]
(i) P (first
ball black and second red)
= P(BR) =
P(B) P (R)
events
are independent]
(iii) P (one
black and other red)
=
P(BR or PB)
=
P(BR) + P(RB)
BR and RB
are mutually exclusive]
= P(B) P(R)
+ P(R), P(B)
independent]
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