question_answer 48)

Find the probability distribution of the number of successes in two tosses of a die, where success is defined as (i) number greater than 4 (ii) six appears on atleast one die.  

Answer:

(i) When a die is tossed, the sample space is {1, 2, 3, 4, 5, 6}        Probability of success =       Let X is the random variable of ?number of successes?.                         P(X = 1) =                   P(X = 2) = P(SS)       Probability distribution                     (ii) Let S = event of getting 6 one atleast one die       = {(1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 1), (6, 2), (6, 2), (6, 3), (6, 4), (6, 5)}        Probability of Success = P(S)             Let X is the random variable of ?number of successes?             P(X = 0) =       P(X =1) = R(S)       Probability distribution is