Answer:
Let
x1 = 1 and x2 = 3 be two real numbers
f(x1)
= f(1) = 1; f(x2) = f(3) = 1
is not
one-one.
Also,
let y = 2
But
range of f is {?1, 0, 1}
Clearly,
there is no value of x for which f(x) = 2
is not onto.
Hence
function
is neither
one-one nor onto.
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