Answer:
t A = {1, 2, 3, 4, 5. 6}
R = {(a, b)
: b = a + 1, a, b A}.
R = {(1, 2),
(2, 3), (3, 4), (4, 5), (5, 6)}.
Reflexive
: As 1 e A and (1, 1)
R
R is not
reflexive.
Symmetric
: As 2, 3
A and (2, 3)
R. But
R is not
symmetric,
Transitive
: As 2. 3 and 4
A
and (2, 3)
R, (3, t (2,4)
R '
R is not transitive.
Hence
R is neither reflexive, nor symmetric, nor transitive.
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