Answer:
Given
f(x) = x2 + 4, Df = R+ = [0, )
Injectivity
: Let x1, x2 be any two elements of R+
such that f(x1) = f(x2)
But
both x1 and x2 are positive real numbers
Therefore
x1 = x2
So
f : R+
is
one-one.
Surjectivity
: Let
then y = f(x)
Corresponding
to every element y of
there
exists a unique element
such
that
is onto.
Hence
f is both one-one and onto
To
find inverse of f :
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